[Swift]LeetCode158. 用Read4来读取N个字符II $ Read N Characte
The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example,it returns 3 if there is only 3 characters left in the file. By using the read4 API,implement the function int read(char *buf,int n) that reads n characters from the file. Note: API:int Read 4(char *BUF)每次从一个文件读取4个字符。 返回值是读取的实际字符数。例如,如果文件中只剩下3个字符,则返回3。 通过使用read4 API,实现从文件中读取n个字符的int read(char*buf,int n)函数。 注: 读取函数可以被多次调用。 1 class Solution { 2 var readPos:Int = 0 3 var writePos:Int = 0 4 var buff:[Character] = [Character](repeating:" ",count:4) 5 func read(_ buf:[Character],_ n:Int) -> Int { 6 var i:Int = 0 7 while (i < n && (readPos < writePos || (readPos = 0) < (writePos = read4(buff)))) 8 { 9 buf[i] = buff[readPos] 10 i += 1 11 readPos += 1 12 } 13 return i 14 } 15 } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |