加入收藏 | 设为首页 | 会员中心 | 我要投稿 李大同 (https://www.lidatong.com.cn/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 百科 > 正文

[Swift]LeetCode179. 最大数 | Largest Number

发布时间:2020-12-14 05:09:02 所属栏目:百科 来源:网络整理
导读:Given a list of non negative integers,arrange them such that they form the largest number. Example 1: Input: Output: "[10,2]210" Example 2: Input: Output: "[3,30,34,5,9]9534330" Note:?The result may be very large,so you need to return a st

Given a list of non negative integers,arrange them such that they form the largest number.

Example 1:

Input: 
Output: "[10,2]210"

Example 2:

Input: 
Output: "
[3,30,34,5,9]9534330"

Note:?The result may be very large,so you need to return a string instead of an integer.


给定一组非负整数,重新排列它们的顺序使之组成一个最大的整数。

示例 1:

输入: 
输出: [10,2]210

示例?2:

输入: 
输出: [3,9]9534330

说明:?输出结果可能非常大,所以你需要返回一个字符串而不是整数。


20ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         var nums = nums
 4         var res:String = String()
 5         nums.sort(by:{(num1:Int,num2:Int) -> Bool in
 6             return String(num1) + String(num2) > String(num2) + String(num1)
 7         })
 8         
 9         for i in 0..<nums.count
10         {
11             res += String(nums[i])
12         }
13         return res[0] == "0" ? "0" : res
14     }
15 }
16 
17 extension String {        
18     //subscript函数可以检索数组中的值
19     //直接按照索引方式截取指定索引的字符
20     subscript (_ i: Int) -> Character {
21         //读取字符
22         get {return self[index(startIndex,offsetBy: i)]}
23     }
24 }

20ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         var arr = nums.compactMap{ return String($0) }
 4         arr.sort{ return $0 + $1 > $1 + $0 }
 5         while arr.count > 1 && arr[0] == "0" {
 6             arr.removeFirst()
 7         }
 8         return arr.joined(separator: "")
 9     }
10 }

24ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3 let s = nums.map({ (i) -> String in
 4         "(i)"
 5     }).sorted { (i,j) -> Bool in
 6          (i + j) > (j + i)
 7         }
 8     if s.count == 0 || s[0] == "0" {
 9         return "0"
10     }
11     return s.reduce("") { (res,t) -> String in
12         res + t
13     }
14     }
15 }

28ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         let strs = nums.map{"($0)"}.sorted { (str1,str2) -> Bool in
 4             return str1 + str2 > str2 + str1
 5         }
 6         let s = strs.joined()
 7         if(s.first != "0"){ return s }
 8         return "0"
 9     }
10 }

28ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         var numsPermuation : [String] = []
 4         
 5         for i in 0..<nums.count {
 6             numsPermuation.append(String(nums[i]))
 7         }
 8         
 9         var result = numsPermuation.map{$0}.sorted(by: {$0 + $1 > $1 + $0}).joined()
10         
11         return result.first == "0" ? "0" : result
12 
13     }
14 }

32ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         var nums = nums
 4         nums.sort{ String($0) + String($1) > String($1) + String($0) }
 5         var result = ""
 6         var flag = false
 7         for i in nums{
 8             if i != 0 {
 9                 flag = true
10             }
11             if flag {
12                 result = result + String(i)   
13             }
14         }
15         if result.count == 0 {
16             result = "0"
17         }
18         return result
19     }
20 }

?32ms

1 class Solution {
2     func largestNumber(_ nums: [Int]) -> String {
3 
4         var res =  nums.map{String($0)}.sorted{ return $0 + $1 > $1 + $0 }.joined()
5         return res.first == "0" ? "0" : res
6     }
7 }

48ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         guard nums.count > 0 else {
 4             return ""
 5         }
 6         
 7         var n = nums.map({ String($0) })
 8         
 9         n.sort { (n1,n2) -> Bool in
10             let s1 = Int(n1 + n2)!
11             let s2 = Int(n2 + n1)!
12             return s1 > s2
13         }
14         
15         
16         let result = n.joined()
17         
18         
19         return n[0] == "0" ? "0" : result
20     }
21 }

48ms

 1 class Solution {
 2     func largestNumber(_ nums: [Int]) -> String {
 3         let array = nums.sorted { return "($0)($1)" > "($1)($0)" }
 4         var result = ""
 5         if let firstNum = array.first,firstNum == 0 {
 6             return "0"
 7         }
 8         for num in array {
 9             result += "(num)"
10         }
11         return result
12     }
13 }

(编辑:李大同)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    推荐文章
      热点阅读