[Swift]LeetCode740. 删除与获得点数 | Delete and Earn

发布时间：2020-12-14 05:02:15 所属栏目：百科来源：网络整理

导读：Given an array? nums ?of integers,you can perform operations on the array. In each operation,you pick any? nums[i] ?and delete it to earn? nums[i] ?points. After,you must delete?every?element equal to? nums[i] - 1 ?or? nums[i] + 1 . You st

Given an array?nums?of integers,you can perform operations on the array.

In each operation,you pick any?nums[i]?and delete it to earn?nums[i]?points. After,you must delete?every?element equal to?nums[i] - 1?or?nums[i] + 1.

You start with 0 points. Return the maximum number of points you can earn by applying such operations.

Example 1:

Input: nums = [3,4,2]
Output: 6
Explanation: 
Delete 4 to earn 4 points,consequently 3 is also deleted.
Then,delete 2 to earn 2 points. 6 total points are earned.?

Example 2:

Input: nums = [2,2,3,4]
Output: 9
Explanation: 
Delete 3 to earn 3 points,deleting both 2‘s and the 4.
Then,delete 3 again to earn 3 points,and 3 again to earn 3 points.
9 total points are earned.?

Note:

The length of?nums?is at most?20000.
Each element?nums[i]?is an integer in the range?[1,10000].

给定一个整数数组?nums?，你可以对它进行一些操作。

每次操作中，选择任意一个?nums[i]?，删除它并获得?nums[i]?的点数。之后，你必须删除每个等于?nums[i] - 1?或?nums[i] + 1?的元素。

开始你拥有 0 个点数。返回你能通过这些操作获得的最大点数。

示例 1:

输入: nums = [3,2]
输出: 6
解释: 
删除 4 来获得 4 个点数，因此 3 也被删除。
之后，删除 2 来获得 2 个点数。总共获得 6 个点数。

示例?2:

输入: nums = [2,4]
输出: 9
解释: 
删除 3 来获得 3 个点数，接着要删除两个 2 和 4 。
之后，再次删除 3 获得 3 个点数，再次删除 3 获得 3 个点数。
总共获得 9 个点数。

注意:

nums的长度最大为20000。
每个整数nums[i]的大小都在[1,10000]范围内。

36ms

 1 class Solution {
 2     func deleteAndEarn(_ nums: [Int]) -> Int {
 3         if nums.count == 0 {
 4             return 0
 5         }
 6         
 7         let maxN = nums.max()!
 8         var M  = [Int](repeating: 0,count: maxN + 1)
 9         var DP = [Int](repeating: 0,count: maxN + 1)
10         
11         for i in 0..<nums.count {
12             M[nums[i]] += nums[i]
13         }
14         
15         DP[0] = M[0]
16         DP[1] = M[1]
17         for i in 2..<M.count {
18             DP[i] = max(DP[i - 2] + M[i],DP[i - 1])
19         }
20         
21         return DP.last!
22     }
23 }

40ms

 1 class Solution {
 2     func deleteAndEarn(_ nums: [Int]) -> Int {
 3         let minValue = nums.min() ?? 0
 4         let maxValue = nums.max() ?? 0
 5         var dp = [Int](repeating: 0,count:maxValue + 1)
 6         for item in nums {
 7             dp[item] += item
 8         }
 9 
10         if maxValue >= 2{
11             for i in 2...maxValue {
12                 dp[i] = max(dp[i-2] + dp[i],dp[i-1])
13             }        
14         }
15 
16         return dp[maxValue]
17     }
18 }

44ms

 1 class Solution {
 2     func deleteAndEarn(_ nums: [Int]) -> Int {
 3         var counts = [Int: Int]()
 4         for num in nums {
 5             counts[num,default: 0] += 1
 6         }
 7         
 8         var prev = -1
 9         var avoid = 0
10         var using = 0
11         
12         for num in counts.keys.sorted() {
13             if num - 1 != prev {
14                 (avoid,using) = (max(avoid,using),num * counts[num]! + max(avoid,using))
15             } else {
16                 (avoid,num * counts[num]! + avoid)
17             }
18             
19             prev = num
20         }        
21         
22         return max(avoid,using)
23     }
24 }

Runtime:?52 ms

Memory Usage:?19.3 MB

 1 class Solution {
 2     func deleteAndEarn(_ nums: [Int]) -> Int {
 3         var sums:[Int] = [Int](repeating:0,count:10001)
 4         for num in nums
 5         {
 6             sums[num] += num
 7         }
 8         for i in 2..<10001
 9         {
10             sums[i] = max(sums[i - 1],sums[i - 2] + sums[i])
11         }
12         return sums[10000]
13     }
14 }

92ms

 1 class Solution {
 2     func deleteAndEarn(_ nums: [Int]) -> Int {
 3         if nums.count == 0 {
 4             return 0
 5         }
 6         if nums.count == 1 {
 7             return nums[0]
 8         }
 9         var numCount: [String: Int] = [:]
10         var dp: [String : Int] = [:]
11         var maxCount = 0
12         for i in 0 ..< nums.count {
13             if let a = numCount["(nums[i])"] {
14                 numCount["(nums[i])"] = a + 1
15             }else {
16                 numCount["(nums[i])"] = 1
17             }
18             if nums[i] > maxCount {
19                 maxCount = nums[i]
20             }
21         }
22         dp["0"] = 0
23         if let a = numCount["1"] {
24             dp["1"] = a
25         }else {
26             dp["1"] = 0
27         }
28         for i in 2 ... maxCount {
29             var a = 0
30             if let e = dp["(i - 1)"] {
31                 a = e
32             }
33             var b = 0
34             var c = 0
35             if let count = dp["(i - 2)"] {
36                 c = count
37             }
38             if let count = numCount["(i)"] {
39                 b = count * i + c
40             }
41             dp["(i)"] = max(a,b)
42         }
43         return dp["(maxCount)"]!
44     }
45 }

（编辑：李大同）

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