swift – 如何在INSendPaymentIntent(SiriKit)中搜索特定联系人

守则背后的思考
我选择使用联系人的姓名来初始搜索联系人,因为如果用户仅指定名字,则使用INPerson显示名称将返回与查询匹配的第一个联系人. (即’支付凯文50美元’将自动选择Kevin Bacon而不是Kevin Spacey).

不幸的是,使用给定的名称将Siri发送到循环中,要求用户一遍又一遍地指定联系人…

题
有没有办法使用联系人的名字搜索联系人而不将Siri发送到循环中？

码

func resolvePayee(forSendPayment intent: INSendPaymentIntent,with completion: (INPersonResolutionResult) -> Void) {
    if let payee = intent.payee {
        var resolutionResult: INPersonResolutionResult?
        var matchedContacts: [INPerson] = []
        let predicate = CNContact.predicateForContacts(matchingName: (payee.nameComponents?.givenName)!)

        do {
            let searchContactsResult = try CNContactStore().unifiedContacts(matching: predicate,keysToFetch:[CNContactGivenNameKey,CNContactFamilyNameKey,CNContactMiddleNameKey,CNContactPhoneNumbersKey,CNContactImageDataKey,CNContactIdentifierKey])
            for contact in searchContactsResult {
                matchedContacts.append(createContact((contact.phoneNumbers.first?.value.stringValue)!,contact: contact))
            }
        } catch {
            completion(INPersonResolutionResult.unsupported())
        }

        switch matchedContacts.count {
            case 2 ... Int.max:
                resolutionResult = INPersonResolutionResult.disambiguation(with: matchedContacts)
            case 1:
                let recipientMatched = matchedContacts[0]
                print("Matched a recipient: (recipientMatched.displayName)")
                resolutionResult = INPersonResolutionResult.success(with: recipientMatched)
            case 0:
                print("This is unsupported")
                resolutionResult = INPersonResolutionResult.unsupported()
            default:
                break
        }

        completion(resolutionResult!)
    } else {
        completion(INPersonResolutionResult.needsValue())
    }
}