swift – 如何覆盖Observable for Testing的清酒?
发布时间:2020-12-14 04:30:19 所属栏目:百科 来源:网络整理
导读:我们正在使用 Swift 2.x(最新)并想要BDD(单元测试)我们的代码.另外,我们也使用 RxSwift.我们的重写方法不会在我们的自定义测试存根中调用.我们的代码: protocol SomethingDeliverable { func fetchSomething(somethingId: String,associatedList: String) -
我们正在使用
Swift 2.x(最新)并想要BDD(单元测试)我们的代码.另外,我们也使用
RxSwift.我们的重写方法不会在我们的自定义测试存根中调用.我们的代码:
protocol SomethingDeliverable { func fetchSomething(somethingId: String,associatedList: String) -> Observable<String> } extension SomethingDeliverable { func fetchSomething(somethingId: String,associatedList: String) -> Observable<String> { return create { observer in return NopDisposable.instance } } } 为了测试,我们有这个测试代码: private class StubSomethingApi: SomethingDeliverable { var responseClosure: ((AnyObserver<String>) -> Void)? func fetchSomething(somethingId: String,associatedList: String) -> Observable<String> { return create { observer in if let responseClosure = self.responseClosure { responseClosure(observer) } return NopDisposable.instance } } } 我们希望返回Observable< T>而不是返回Observable< String>的fetchSomething.并让StubSomethingAPI成功覆盖它以测试sakes. 解决方法
这是你想要的?
protocol SomethingDeliverable { associatedtype Element func fetchSomething(somethingId: String,associatedList: String) -> Observable<Element> } extension SomethingDeliverable { func fetchSomething(somethingId: String,associatedList: String) -> Observable<Element> { return create { observer in return NopDisposable.instance } } } private class StubSomethingApi<T>: SomethingDeliverable { typealias Element = T var responseClosure: ((AnyObserver<T>) -> Void)? func fetchSomething(somethingId: String,associatedList: String) -> Observable<T> { return create { observer in if let responseClosure = self.responseClosure { responseClosure(observer) } return NopDisposable.instance } } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |