在Swift中将可变数量的args从一个函数传递到另一个函数

参见英文答案 > Passing an array to a function with variable number of args in Swift????????????????????????????????????6个
Swift language guide向您展示了如何创建接受可变参数的函数.它还指出,参数被收集到一个数组中.

因此,如果我有示例函数sumOf,如指南中所述：

func sumOf(numbers: Int...) -> Int {
    var sum = 0
    for number in numbers {
        sum += number
    }
    return sum
}

第二个函数也采用可变数量的参数,如何将第二个函数从第二个传递到第一个？

func avgOf(numbers: Int...) -> Int {
    // Can't do this without the complier complaining about:
    // "error: could not find an overload for '__conversion' that accepts the supplied arguments"
    var sum = sumOf(numbers)
    var avg = sum / numbers.count
    return avg
}

func sumOf(numbers: Int...) -> Int {
    return sumOf(numbers)
}
func sumOf(numbers: Int[]) -> Int {
    var sum = 0
    for number in numbers {
        sum += number
    }
    return sum
}