swift3 – swift 3.0 UIBarButtonItem动作不起作用
发布时间:2020-12-14 02:28:05 所属栏目:百科 来源:网络整理
导读:let leftbarbuttonitem = UIBarButtonItem(title:"Reset",style: .plain,target: self,action: #selector(tapResetButton(_:))) func tapResetButton(_ sender:UIBarButtonItem){ count = 0 numberLabel.text = "0" } 该操作无法响应click事件.我添加了断点
let leftbarbuttonitem = UIBarButtonItem(title:"Reset",style: .plain,target: self,action: #selector(tapResetButton(_:))) func tapResetButton(_ sender:UIBarButtonItem){ count = 0 numberLabel.text = "0" } 该操作无法响应click事件.我添加了断点然后发现它甚至没有进入函数.我不知道我的代码有什么问题.任何答案将不胜感激.提前致谢.
在ViewDidLoad()中声明UIBarButton override func viewDidLoad() { super.viewDidLoad() let logout: UIBarButtonItem = UIBarButtonItem.init(title: "Logout",action: #selector(ViewController.logOut)) } func logOut() { print("LogOut") } 声明UIBarButtonItem OutSide ViewDidLoad() var logout:UIBarButtonItem = UIBarButtonItem() override func viewDidLoad() { super.viewDidLoad() logout = UIBarButtonItem.init(title: "Logout",action: #selector(ViewController.logOut)) } func logOut() { print("LogOut") } 完全声明viewDidLoad() lazy var logout: UIBarButtonItem = { UIBarButtonItem.init(title: "Logout",action: #selector(ViewController.logOut)) }() 任何应该工作. 对于action参数,您可以明确指定ViewController名称,也可以只说自己. action: #selector(self.logOut) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |