swift – arkit锚点或节点在相机中可见并且坐在平截头体的左侧或
如何检测ARAnchor当前是否在相机中可见,我需要测试相机视图何时发生变化.
我想在不在屏幕上时将箭头放在屏幕边缘指向锚点的方向.我需要知道节点是否位于平截头体的左侧或右侧. 我现在正在这样做,但是它表示如果不是,并且X值看起来不对,那么引脚是可见的吗?也许渲染器视锥体与屏幕相机不匹配? var deltaTime = TimeInterval() public func renderer(_ renderer: SCNSceneRenderer,updateAtTime time: TimeInterval) { deltaTime = time - lastUpdateTime if deltaTime>1{ if let annotation = annotationsByNode.first { let node = annotation.key.childNodes[0] if !renderer.isNode(node,insideFrustumOf: renderer.pointOfView!) { print("Pin is not visible"); }else { print("Pin is visible"); } let pnt = renderer.projectPoint(node.position) print("pos ",pnt.x," ",renderer.pointOfView!.position) } lastUpdateTime = time } } 更新:代码用于显示节点是否可见,如何判断节点相对于相机平截头的左或右方向? UPDATE2!正如Bhanu Birani的建议答案 let screenWidth = UIScreen.main.bounds.width let screenHeight = UIScreen.main.bounds.height let leftPoint = CGPoint(x: 0,y: screenHeight/2) let rightPoint = CGPoint(x: screenWidth,y: screenHeight/2) let leftWorldPos = renderer.unprojectPoint(SCNVector3(leftPoint.x,leftPoint.y,0)) let rightWorldPos = renderer.unprojectPoint(SCNVector3(rightPoint.x,rightPoint.y,0)) let distanceLeft = node.position - leftWorldPos let distanceRight = node.position - rightWorldPos let dir = (isVisible) ? "visible" : ( (distanceLeft.x<distanceRight.x) ? "left" : "right") 我最终使用了屏幕左右两侧的Bhanu Birani的想法,但是我获得了不同的世界位置,unProjectPoint并且还获得了距离的标量值,我将其与左/右方向进行比较.也许有更好的方法,但它对我有用 public func renderer(_ renderer: SCNSceneRenderer,updateAtTime time: TimeInterval) { deltaTime = time - lastUpdateTime if deltaTime>0.25{ if let annotation = annotationsByNode.first { guard let pointOfView = renderer.pointOfView else {return} let node = annotation.key.childNodes[0] let isVisible = renderer.isNode(node,insideFrustumOf: pointOfView) let screenWidth = UIScreen.main.bounds.width let screenHeight = UIScreen.main.bounds.height let leftPoint = CGPoint(x: 0,y: screenHeight/2) let rightPoint = CGPoint(x: screenWidth,y: screenHeight/2) let leftWorldPos = renderer.unprojectPoint(SCNVector3(leftPoint.x,0)) let rightWorldPos = renderer.unprojectPoint(SCNVector3(rightPoint.x,0)) let distanceLeft = node.worldPosition.distance(vector: leftWorldPos) let distanceRight = node.worldPosition.distance(vector: rightWorldPos) //let pnt = renderer.projectPoint(node.worldPosition) //guard let pnt = renderer.pointOfView!.convertPosition(node.position,to: nil) else {return} let dir = (isVisible) ? "visible" : ( (distanceLeft<distanceRight) ? "left" : "right") print("dir",dir,leftWorldPos,rightWorldPos) lastDir=dir delegate?.nodePosition?(node:node,pos: dir) }else { delegate?.nodePosition?(node:nil,pos: lastDir ) } lastUpdateTime = time } extension SCNVector3 { /** * Returns the length (magnitude) of the vector described by the SCNVector3 */ func length() -> Float { return sqrtf(x*x + y*y + z*z) } /** * Calculates the distance between two SCNVector3. Pythagoras! */ func distance(vector: SCNVector3) -> Float { return (self - vector).length() } }
从以下屏幕位置投射光线:
> leftPoint = CGPoint(0,screenHeight / 2)(屏幕中间左侧) 将CGPoint转换为世界位置: > leftWorldPos = convertCGPointToWorldPosition(leftPoint) 计算两个世界位置的节点距离: > distanceLeft = node.position – leftWorldPos 比较距离以找到到节点的最短距离.使用最短距离矢量来定位对象的方向箭头. 以下是来自tsukimi的代码,用于检查对象是在屏幕的右侧还是在左侧: public func renderer(_ renderer: SCNSceneRenderer,pos: lastDir ) } lastUpdateTime = time } 以下是帮助对vector执行操作的类 extension SCNVector3 { init(_ vec: vector_float3) { self.x = vec.x self.y = vec.y self.z = vec.z } func length() -> Float { return sqrtf(x * x + y * y + z * z) } mutating func setLength(_ length: Float) { self.normalize() self *= length } mutating func setMaximumLength(_ maxLength: Float) { if self.length() <= maxLength { return } else { self.normalize() self *= maxLength } } mutating func normalize() { self = self.normalized() } func normalized() -> SCNVector3 { if self.length() == 0 { return self } return self / self.length() } static func positionFromTransform(_ transform: matrix_float4x4) -> SCNVector3 { return SCNVector3Make(transform.columns.3.x,transform.columns.3.y,transform.columns.3.z) } func friendlyString() -> String { return "((String(format: "%.2f",x)),(String(format: "%.2f",y)),z)))" } func dot(_ vec: SCNVector3) -> Float { return (self.x * vec.x) + (self.y * vec.y) + (self.z * vec.z) } func cross(_ vec: SCNVector3) -> SCNVector3 { return SCNVector3(self.y * vec.z - self.z * vec.y,self.z * vec.x - self.x * vec.z,self.x * vec.y - self.y * vec.x) } } extension SCNVector3{ func distance(receiver:SCNVector3) -> Float{ let xd = receiver.x - self.x let yd = receiver.y - self.y let zd = receiver.z - self.z let distance = Float(sqrt(xd * xd + yd * yd + zd * zd)) if (distance < 0){ return (distance * -1) } else { return (distance) } } } 以下是将抽头位置或任何CGPoint转换为世界变换的代码段. @objc func handleTap(_ sender: UITapGestureRecognizer) { // Take the screen space tap coordinates and pass them to the hitTest method on the ARSCNView instance let tapPoint = sender.location(in: sceneView) let result = sceneView.hitTest(tapPoint,types: ARHitTestResult.ResultType.existingPlaneUsingExtent) // If the intersection ray passes through any plane geometry they will be returned,with the planes // ordered by distance from the camera if (result.count > 0) { // If there are multiple hits,just pick the closest plane if let hitResult = result.first { let finalPosition = SCNVector3Make(hitResult.worldTransform.columns.3.x + insertionXOffset,hitResult.worldTransform.columns.3.y + insertionYOffset,hitResult.worldTransform.columns.3.z + insertionZOffset ); } } } 以下是在没有找到飞机时获得命中测试结果的代码. // check what nodes are tapped let p = gestureRecognize.location(in: scnView) let hitResults = scnView.hitTest(p,options: [:]) // check that we clicked on at least one object if hitResults.count > 0 { // retrieved the first clicked object let result = hitResults[0] } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |