快速错误的字符串init(格式…方法?[复制]
发布时间:2020-12-14 02:25:10 所属栏目:百科 来源:网络整理
导读:参见英文答案 cannot find an initializer for type ‘String’ that accepts an argument list of type ‘(format: String,argument: UInt321个 let elem1 = "1"let elem2 = "2"let array = [elem1,elem2]let format = "%@ != %@"//compiler error//can't f
参见英文答案 >
cannot find an initializer for type ‘String’ that accepts an argument list of type ‘(format: String,argument: UInt321个
let elem1 = "1" let elem2 = "2" let array = [elem1,elem2] let format = "%@ != %@" //compiler error //can't find an initializer for type... let str = String(format: format,arguments: elem1,elem2) //no errors but wrong output //("%@ != %@","1","2") let str = String(format: format,_arguments: elem1,elem2) //runtime error //fatal error: can't unsafeBitCast between types of different sizes //this is what I need let str = String(format: format,arguments: array) //only this works with the right output //1 != 2 let str = String(format: format,arguments: [elem1,elem2]) print(str) 在xcode7 beta和xcode6.3中测试过,我现在找不到解决方法
使用此语法(XCode 7):
import Foundation let elem1 = "1" let elem2 = "2" let format = "%@ != %@" let str = String(format: format,elem1,elem2) // "1 !=2" print(str) // "1 != 2n" 诀窍是用格式指定重载的ctor:并跳过参数:all all. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |