最新测试版中的Swift C void *和void **指针(4)
发布时间:2020-12-14 02:23:29 所属栏目:百科 来源:网络整理
导读:在以前的测试版中,我能够将指向任何东西的指针传递给C做类似的事情 var aString : NSString = "This is a string" // create an NSStringvar anUnmanaged = Unmanaged.passUnretained(aString) // take an unmanaged pointervar opaque : COpaquePointer = a
在以前的测试版中,我能够将指向任何东西的指针传递给C做类似的事情
var aString : NSString = "This is a string" // create an NSString var anUnmanaged = Unmanaged.passUnretained(aString) // take an unmanaged pointer var opaque : COpaquePointer = anUnmanaged.toOpaque() // convert it to a COpaquePointer var mut : CMutablePointer = &opaque // this is a CMutablePointer doSomething(mut) // pass the pointer to an helper function written in C 使用C函数如下: void doSomething(void ** ptr) { // do something with the pointer,change it and make it point to another nsstring for example } 现在,(肯定在Beta4中,甚至可能在Beta3中)从C转换为Swift的语法已经改变 之前,doSomething函数期待CMutablePointer(现在已从Swift中删除) UnsafePointer<UnsafePointer<()>> ()是Void的类型 所以,语法上的说话更清楚. 有什么建议吗?
这对我有用:
var str = "Hello,playground" var p: UnsafePointer<Void> = unsafeAddressOf(str) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |