正则表达式—获取、分隔、匹配
发布时间:2020-12-14 01:42:40 所属栏目:百科 来源:网络整理
导读:// 获取public static void fuctionDemo_5() {String str = "yang cheng yong ben dan ba shi de ta hen sha";String regex = "b[a-z]{3}b";Pattern p = Pattern.compile(regex);Matcher m = p.matcher(str);while (m.find()) {System.out.println(m.gro
// 获取 public static void fuctionDemo_5() { String str = "yang cheng yong ben dan ba shi de ta hen sha"; String regex = "b[a-z]{3}b"; Pattern p = Pattern.compile(regex); Matcher m = p.matcher(str); while (m.find()) { System.out.println(m.group()); } } public static void fuctionDemo_4() { String str = "18758183839"; str = str.replaceAll("(d{3})d{4}(d{4})","$1****$2"); System.out.println(str); } // 分割1 public static void fuctionDemo_3() { String str = "yang8888cheng222yong"; str = str.replaceAll("(.)1+","$1"); System.out.println(str); } // 切割2 public static void fuctionDemo_2() { String s1 = "yang cheng yong beng dan"; String[] names = s1.split(" +"); for (String name : names) { System.out.println(name); } String s2 = "yang###sha@@@bi"; String[] names2 = s2.split("(.)1+"); for (String name : names2) { System.out.println(name); } } // 匹配手机号码是否正确 public static void fuctionDemo_1() { String num = "15958184259"; String regex = "1[358][0-9]{9}"; boolean b = num.matches(regex); System.out.println(num + ":" + b); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |