LeetCode 86 Valid Number
发布时间:2020-12-14 01:33:10 所属栏目:百科 来源:网络整理
导读:Validate if a given string is numeric. Some examples: "0" = true " 0.1 " = true "abc" = false "1 a" = false "2e10" = true Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before imp
Validate if a given string is numeric.
Some examples: "0" => true " 0.1 " => true "abc" => false "1 a" => false "2e10" => true Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one. 分析: 判断字符串是否满足满足某些规则,应该想到正则表达式。 public class Solution { public boolean isNumber(String s) { if(s == null || s.trim().length()==0) return false; String regex = "[-+]?(d+.?|.d+)d*(e[-+]?d+)?"; if(s.trim().matches(regex)) return true; return false; } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |