使用[a-z]正则表达式在Java中拆分String

发布时间：2020-12-13 21:52:59 所属栏目：百科来源：网络整理

导读：我有两个 regexpressions： [a-c] : any character from a-c[a-z] : any character from a-z 并测试： public static void main(String[] args) { String s = "abcde"; String[] arr1 = s.split("[a-c]"); String[] arr2 = s.split("[a-z]"); System.out.pri

我有两个 regexpressions：

[a-c] : any character from a-c

[a-z] : any character from a-z

并测试：

public static void main(String[] args) {
    String s = "abcde";
    String[] arr1 = s.split("[a-c]");
    String[] arr2 = s.split("[a-z]");

    System.out.println(arr1.length); //prints 4 : "","","de"
    System.out.println(arr2.length); //prints 0 
}

为什么第二次分裂表现得像这样？我希望有一个带有6个空字符串“”结果的reslut.

根据 the documentation of the single-argument String.split：

This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.

要保留尾随字符串,可以使用双参数版本,并指定负限制：

String s = "abcde";
    String[] arr1 = s.split("[a-c]",-1); // ["","de"]
    String[] arr2 = s.split("[a-z]",""]

（编辑：李大同）

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