PostgreSQL 按周、月、天 统计问题
PostgreSQL 实现按月按年,按日统计 分组统计:实质是把时间戳格式化成字符串,然后分组统计。 例如: select http://javatophp.iteye.com/blog/768306 --------------------------------------------------------------------------------------------------------- 按周统计:这个之能写程序拼sql了或者写存储过程。 愉快的找到7天分界点,http://www.jianshu.com/p/54e851518151 例如: select generate_series的时间递增包含:(前面的数字可以修改) 1 seconds 怎么拼呢,如下: select count(case when prevent_rank=1 and risk_rank>=2 and create_time>='2017-05-01 00:00:00' and create_time<'2017-05-08 00:00:00' then 'week1' end) "week0501-0508",count(case when prevent_rank=1 and risk_rank>=2 and create_time>='2017-05-01 00:00:00' and create_time<'2017-05-08 00:00:00' and drug_aspl=1 then 'week1' end) "week0501-0508_drug",sum(case when prevent_rank=1 and risk_rank>=2 and create_time>='2017-05-08 00:00:00' and create_time<'2017-05-15 00:00:00' then 1 else 0 end) "week0508-0515",sum(case when prevent_rank=1 and risk_rank>=2 and create_time>='2017-05-08 00:00:00' and create_time<'2017-05-15 00:00:00' and drug_aspl=1 then 1 else 0 end) "week0508-0515_drug",from record_table (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |