获取Sqlite数据库中的表名和字段名
发布时间:2020-12-12 20:03:18 所属栏目:百科 来源:网络整理
导读:代码很简略,没有添加太多的保护 NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask,YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *path = [documentsDirectory stringByAppendingPa
代码很简略,没有添加太多的保护
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask,YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *path = [documentsDirectory stringByAppendingPathComponent:@"database_name"]; sqlite3 *database; sqlite3_open([path UTF8String],&database); char *errorMsg; const char *createSQL = "CREATE TABLE IF NOT EXISTS PEOPLE (ID INTEGER PRIMARY KEY AUTOINCREMENT,FIELD_DATA TEXT)"; int result = sqlite3_exec(database,createSQL,NULL,&errorMsg); sqlite3_stmt *statement; if (result == SQLITE_OK) { const char *getTableInfo = "select * from sqlite_master where type='table' order by name;"; result = sqlite3_prepare_v2(database,getTableInfo,-1,&statement,nil); while (sqlite3_step(statement) == SQLITE_ROW) { char *nameData = (char *)sqlite3_column_text(statement,1); NSString *tableName = [[NSString alloc] initWithUTF8String:nameData]; NSLog(@"name:%@",tableName); } const char *getColumn = "PRAGMA table_info(PEOPLE)"; result = sqlite3_prepare_v2(database,getColumn,nil); while (sqlite3_step(statement) == SQLITE_ROW) { char *nameData = (char *)sqlite3_column_text(statement,1); NSString *columnName = [[NSString alloc] initWithUTF8String:nameData]; NSLog(@"columnName:%@",columnName); } sqlite3_finalize(statement); } sqlite3_close(database); 指出一点: sqlite_master表结构 CREATE TABLE sqlite_master ( type TEXT,name TEXT,tbl_name TEXT,rootpage INTEGER,sql TEXT ); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |