SQLite: Cannot bind argument at index 1 because the index is

SQLite: Cannot bind argument at index 1 because the index is out of range. The statement has 0 parameters

SQLite出现了这样的错误

12-25 22:52:50.252: E/AndroidRuntime(813): Caused by: java.lang.IllegalArgumentException: Cannot bind argument at index 1 because the index is out of range.  The statement has 0 parameters.
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteProgram.bind(SQLiteProgram.java:212)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteProgram.bindString(SQLiteProgram.java:166)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteProgram.bindAllArgsAsStrings(SQLiteProgram.java:200)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDirectCursorDriver.query(SQLiteDirectCursorDriver.java:47)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.rawQueryWithFactory(SQLiteDatabase.java:1314)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.queryWithFactory(SQLiteDatabase.java:1161)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.query(SQLiteDatabase.java:1032)
12-25 22:52:50.252: E/AndroidRuntime(813):  at android.database.sqlite.SQLiteDatabase.query(SQLiteDatabase.java:1200)

代码如下

public Player getPlayer(String name) {
    SQLiteDatabase db = this.getReadableDatabase();

    String[] projection = {
            PlayerEntry.COLUMN_NAME_PLAYER_NAME,PlayerEntry.COLUMN_NAME_PLAYED_GAMES,};

    String selection =  PlayerEntry.COLUMN_NAME_PLAYER_NAME ;
    String[] selectionArgs = new String[1];
    selectionArgs[0] = name;

    Cursor cursor = db.query(
            PlayerEntry.TABLE_NAME,// The table to query
            projection,// The columns to return
            selection,// The columns for the WHERE clause
            selectionArgs,// The values for the WHERE clause
            null,// don't group the rows
            null,// don't filter by row groups
            null                                 // The sort order
            );

    if (cursor != null)
        cursor.moveToFirst();

解决方法如下

String selection =  PlayerEntry.COLUMN_NAME_PLAYER_NAME + "=?";

（编辑：李大同）

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