Sqlite python sqlite3.OperationalError：数据库被锁定

基本上我试图将数据从table1复制到table2,并根据某些其他应用程序发生在table1上的更改将数据插入到table2中.

看起来我错过了一些部分.

import sqlite3

conn = sqlite3.connect("/home/sid/.Skype/testmasterut/main.db")
cursor = conn.cursor()

createLogTableSql = """create table IF NOT EXISTS sid_log as select id as "s_id",author as "s_author",timestamp as "s_timestamp",edited_by as "s_editedby",edited_timestamp as "s_edited_timestamp",body_xml as "s_body_xml" from Messages"""

cursor.execute(createLogTableSql)
conn.commit()
print "Table to save the old messages has been created"

selectLog = """ select * from sid_log """
original_table = cursor.execute(selectLog)

cursor2 = conn.cursor()
cursor3 = conn.cursor()
cursor4 = conn.cursor()

InsertTest = """ insert or ignore into sid_log (s_id,s_author,s_timestamp,s_editedby,s_edited_timestamp,s_body_xml)
select id,author,timestamp,edited_by,edited_timestamp,body_xml from Messages where id not in (select s_id from sid_log where s_id = id) and edited_by is NULL and edited_timestamp is NULL
"""

EditedTest = """ select * from Messages where id in (select s_id from sid_log where s_id = id) and edited_by is not NULL and edited_timestamp is not NULL"""
conn.close()

while True:
    conn2 = sqlite3.connect("/home/sid/.Skype/testmasterut/main.db",timeout=3)
    conn2.execute(InsertTest)

    print "Total number of rows changed:",conn.total_changes
    EditedTest2 = """ select * from Messages where id in (select s_id from sid_log where s_id = id) and edited_by is not NULL and edited_timestamp is not NULL"""
    edited_list = conn2.execute(EditedTest2)
    conn2.commit()
    conn2.close()
    # for row in edited_list:
    #   queryString = "SELECT * FROM sid_log WHERE s_id IN (%s)" % str(row[0])
    #   original_message = conn.execute(queryString)
    #   for org_row in original_message:
    #       print "Message edited from",org_row[5],"to",row[5]

编辑
以下是追溯

Traceback (most recent call last):
  File "try2.py",line 28,in <module>
    conn2.execute(InsertTest)
sqlite3.OperationalError: database is locked

我使用PyCharm,发现我正在处理的脚本的几个实例都在运行.这通常是由于我正在测试的代码中的错误,但它保持活动状态(因此与db的连接仍处于活动状态).关闭那些(停止所有过程)并再试一次 – 它每次都适合我！

如果有人知道一段时间后让它超时的方法,请评论此解决方案.我尝试了cur.execute(“PRAGMA busy_timeout = 30000”)(从类似问题的另一个线程中找到)但它似乎没有做任何事情.

（编辑：李大同）

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