使用sqlite / PHP获得两个不同行/列中两个数字的方差和标准差
发布时间:2020-12-12 18:57:55 所属栏目:百科 来源:网络整理
导读:我有一个具有以下结构的SQLite数据库: rowid ID startTimestamp endTimestamp subject1 00:50:c2:63:10:1a 1000 1090 entrance2 00:50:c2:63:10:1a 1100 1270 entrance3 00:50:c2:63:10:1a 1300 1310 door14 00:50:c2:63:10:1a 1370 1400 entrance... 我在
我有一个具有以下结构的SQLite数据库:
rowid ID startTimestamp endTimestamp subject 1 00:50:c2:63:10:1a 1000 1090 entrance 2 00:50:c2:63:10:1a 1100 1270 entrance 3 00:50:c2:63:10:1a 1300 1310 door1 4 00:50:c2:63:10:1a 1370 1400 entrance . . . 我在这里准备了一个sqlfiddle:http://sqlfiddle.com/#!2/fe8c6/2 使用此SQL-Query,我可以获得endTime和一行与下一行之间的startTime之间的平均差异,按主题和ID排序: SELECT id,( MAX(endtimestamp) - MIN(startTimestamp) - SUM(endtimestamp-startTimestamp) ) / (COUNT(*)-1) AS averageDifference FROM table1 WHERE ID = '00:50:c2:63:10:1a' AND subject = 'entrance' GROUP BY id; 我的问题:要计算平均值是没有问题的,这就是查询.但我怎么能 解决方法首先通过将表连接到自身并按ID分组来找到感兴趣的时间差,然后找到平均值,方差为V(x)= E(x ^ 2) – (E(x))^ 2,标准差为sqrt (V)给出SELECT ID,AVG(diff) AS average,AVG(diff*diff) - AVG(diff)*AVG(diff) AS variance,SQRT(AVG(diff*diff) - AVG(diff)*AVG(diff)) AS stdev FROM (SELECT t1.id,t1.endTimestamp,min(t2.startTimeStamp) - t1.endTimestamp AS diff FROM table1 t1 INNER JOIN table1 t2 ON t2.ID = t1.ID AND t2.subject = t1.subject AND t2.startTimestamp > t1.startTimestamp -- consider only later startTimestamps WHERE t1.subject = 'entrance' GROUP BY t1.id,t1.endTimestamp) AS diffs GROUP BY ID (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |