更新查询sqlite – Android

发布时间：2020-12-12 18:51:23 所属栏目：百科来源：网络整理

导读：我无法在我的 Android应用程序中破解SQLite中的简单更新查询..这是查询, int fav = 1;Cursor c = sqliteDB.rawQuery("UPDATE "+ MyConstants.TABLE_NAME + " SET "+MyConstants.TABLE_NAME+"."+MyConstants.ISFAV+ " = "+fav+ " WHERE " +MyConstants.TABLE_

我无法在我的 Android应用程序中破解SQLite中的简单更新查询..这是查询,

int fav = 1;
Cursor c = sqliteDB.rawQuery("UPDATE "+ MyConstants.TABLE_NAME + " SET "+MyConstants.TABLE_NAME+"."+MyConstants.ISFAV+ " = "+fav+ " WHERE " +MyConstants.TABLE_NAME+"."+MyConstants.WORD_NAME+ " = ""+word_name+""",null);

这是例外,

07-06 23:41:48.723: E/AndroidRuntime(1102): FATAL EXCEPTION: main
07-06 23:41:48.723: E/AndroidRuntime(1102): android.database.sqlite.SQLiteException: near ".": syntax error (code 1):,while compiling: UPDATE words SET words.isfavor = 1 WHERE words.word = "hello"
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method)
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:1013)
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteConnection.prepare(SQLiteConnection.java:624)
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteSession.prepare(SQLiteSession.java:588)
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteProgram.<init>(SQLiteProgram.java:58)
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteQuery.<init>(SQLiteQuery.java:37)
07-06 23:41:48.723: E/AndroidRuntime(1102):     at android.database.sqlite.SQLiteDirectCursorDriver.query(SQLiteDirectCursorDriver.java:44)

解决方法

你不断使用表名.它应该更像是这样的：

int fav = 1;
Cursor c = sqliteDB.rawQuery("UPDATE "+ MyConstants.TABLE_NAME + " SET "+ MyConstants.ISFAV + " = "+fav+ " WHERE " + MyConstants.WORD_NAME + " = ""+word_name+""",null);

这应该给你一个看起来更像这样的结果查询：

UPDATE words SET isfavor = 1 WHERE word = "hello"

（编辑：李大同）

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