oracle – PLS-00103:遇到以下其中一项时遇到符号“;”:
发布时间:2020-12-12 15:13:59 所属栏目:百科 来源:网络整理
导读:我的代码有什么问题 SQL declare 2 mark number :=50; 3 begin 4 mark := mark; 5 if (mark between 85 and 100) 6 then 7 dbms_output.put_line('mark is A '); 8 else if (mark between 50 and 65) then 9 dbms_output.put_line('mark is D '); 10 else if
我的代码有什么问题
SQL> declare 2 mark number :=50; 3 begin 4 mark :=& mark; 5 if (mark between 85 and 100) 6 then 7 dbms_output.put_line('mark is A '); 8 else if (mark between 50 and 65) then 9 dbms_output.put_line('mark is D '); 10 else if (mark between 66 and 75) then 11 dbms_output.put_line('mark is C '); 12 else if (mark between 76 and 84) then 13 dbms_output.put_line('mark is B'); 14 else 15 dbms_output.put_line('mark is F'); 16 end if; 17 end; 18 / Enter value for mark: 65 old 4: mark :=& mark; new 4: mark :=65; end; * 问题是else和if是两个运算符.由于你打开一个新的’if’,你需要一个相应的’end if’. 从而: declare mark number :=50; begin mark :=& mark; if (mark between 85 and 100) then dbms_output.put_line('mark is A '); else if (mark between 50 and 65) then dbms_output.put_line('mark is D '); else if (mark between 66 and 75) then dbms_output.put_line('mark is C '); else if (mark between 76 and 84) then dbms_output.put_line('mark is B'); else dbms_output.put_line('mark is F'); end if; end if; end if; end if; end; / 或者你可以使用elsif: declare mark number :=50; begin mark :=& mark; if (mark between 85 and 100) then dbms_output.put_line('mark is A '); elsif (mark between 50 and 65) then dbms_output.put_line('mark is D '); elsif (mark between 66 and 75) then dbms_output.put_line('mark is C '); elsif (mark between 76 and 84) then dbms_output.put_line('mark is B'); else dbms_output.put_line('mark is F'); end if; end; / (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |