oracle使用substr instr实现类似于java substring的功能

发布时间：2020-12-12 15:04:27 所属栏目：百科来源：网络整理

导读：select cast(substr(a.str1,instr(a.str1,';',1,'27') + 1,(instr(a.str1,'28') - instr(a.str1,'27') - 1)) as varchar2(10)) as value1 from table1 a where (length(a.str1) - length(replace(a.str1,''))) = 29 and cast(substr(a.str1,'27') - 1)) as v

select cast(substr(a.str1,instr(a.str1,';',1,'27') + 1,(instr(a.str1,'28') -
                   instr(a.str1,'27') - 1)) as varchar2(10)) as value1
  from table1 a
 where (length(a.str1) - length(replace(a.str1,''))) = 29
   and cast(substr(a.str1,'27') - 1)) as varchar2(10)) is not null;

（编辑：李大同）

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