oracle 和sqlserver的update语句区别
发布时间:2020-12-12 13:27:07 所属栏目:百科 来源:网络整理
导读:sqlserver的update语句 update e set score = score1 from PERF_DEPT_KPI eleft join (select score score1,SUPPER_WEIDU_ID from(SELECT SUM (PDK.SCORE) score,pdk.grade,PD.SUPPER_WEIDU_IDFROM PERF_DEPT_KPI PDKLEFT JOIN PERF_DIMENSION PD ON PDK.WEI
sqlserver的update语句 update e set score = score1 from PERF_DEPT_KPI e left join (select score score1,SUPPER_WEIDU_ID from( SELECT SUM (PDK.SCORE) score,pdk.grade,PD.SUPPER_WEIDU_ID FROM PERF_DEPT_KPI PDK LEFT JOIN PERF_DIMENSION PD ON PDK.WEIDU_ID = PD.WEIDU_ID WHERE PD.IS_ADD = 1 AND PDK.GRADE = 2 AND PDK.PROJECT_ID =29 GROUP BY PD.SUPPER_WEIDU_ID,pdk.grade) a)b on e.weidu_id = b.SUPPER_WEIDU_ID where e.grade=1 and e.weidu_id in(select DISTINCT SUPPER_WEIDU_ID from PERF_DIMENSION c where c.is_add =1 and project_id =29) oracle 的 update语句 update PERF_DEPT_KPI a set SCORE = (select score from ( select sum(PDK.SCORE) score,PD.SUPPER_WEIDU_ID from PERF_DEPT_KPI PDK LEFT JOIN PERF_DIMENSION PD on PDK.WEIDU_ID= PD.WEIDU_ID where PD.IS_ADD=1 and PDK.PROJECT_ID=58095 and PDK.GRADE=2 group by PD.SUPPER_WEIDU_ID,pdk.grade ) b where a.WEIDU_ID= b.SUPPER_WEIDU_ID and a.grade=1 ) where a.grade=1 and a.weidu_id in(select DISTINCT SUPPER_WEIDU_ID from PERF_DIMENSION c where c.is_add =1 and project_id =58095) (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |